Base | Representation |
---|---|
bin | 11101011100111111110… |
… | …10000011110111111001 |
3 | 10120202011000202021122010 |
4 | 32232133322003313321 |
5 | 113040034012041441 |
6 | 2052523442320133 |
7 | 133054210010445 |
oct | 16563772036771 |
9 | 3522130667563 |
10 | 1012000112121 |
11 | 360206753829 |
12 | 144170959049 |
13 | 7457b46c3bb |
14 | 36da4093825 |
15 | 1b4d000a116 |
hex | eb9fe83df9 |
1012000112121 has 32 divisors (see below), whose sum is σ = 1370764541952. Its totient is φ = 664037821440.
The previous prime is 1012000112119. The next prime is 1012000112173. The reversal of 1012000112121 is 1212110002101.
It is not a de Polignac number, because 1012000112121 - 21 = 1012000112119 is a prime.
It is a super-2 number, since 2×10120001121212 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1012000112097 and 1012000112106.
It is not an unprimeable number, because it can be changed into a prime (1012000112621) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 69350536 + ... + 69365126.
It is an arithmetic number, because the mean of its divisors is an integer number (42836391936).
Almost surely, 21012000112121 is an apocalyptic number.
It is an amenable number.
1012000112121 is a deficient number, since it is larger than the sum of its proper divisors (358764429831).
1012000112121 is a wasteful number, since it uses less digits than its factorization.
1012000112121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16053.
The product of its (nonzero) digits is 8, while the sum is 12.
Adding to 1012000112121 its reverse (1212110002101), we get a palindrome (2224110114222).
The spelling of 1012000112121 in words is "one trillion, twelve billion, one hundred twelve thousand, one hundred twenty-one".
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