Base | Representation |
---|---|
bin | 1001001101000011111110… |
… | …1011000101110100111001 |
3 | 1022211110111222111101121112 |
4 | 2103100333223011310321 |
5 | 2311301240332210131 |
6 | 33305022521450105 |
7 | 2063101211656115 |
oct | 223207753056471 |
9 | 38743458441545 |
10 | 10120011210041 |
11 | 3251966555437 |
12 | 11753ab340935 |
13 | 58540b769145 |
14 | 26db4db52745 |
15 | 1283a0db002b |
hex | 9343fac5d39 |
10120011210041 has 2 divisors, whose sum is σ = 10120011210042. Its totient is φ = 10120011210040.
The previous prime is 10120011210017. The next prime is 10120011210053. The reversal of 10120011210041 is 14001211002101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9520464525625 + 599546684416 = 3085525^2 + 774304^2 .
It is a cyclic number.
It is not a de Polignac number, because 10120011210041 - 214 = 10120011193657 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10120011209998 and 10120011210025.
It is not a weakly prime, because it can be changed into another prime (10120011210641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060005605020 + 5060005605021.
It is an arithmetic number, because the mean of its divisors is an integer number (5060005605021).
Almost surely, 210120011210041 is an apocalyptic number.
It is an amenable number.
10120011210041 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120011210041 is an equidigital number, since it uses as much as digits as its factorization.
10120011210041 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16, while the sum is 14.
Adding to 10120011210041 its reverse (14001211002101), we get a palindrome (24121222212142).
The spelling of 10120011210041 in words is "ten trillion, one hundred twenty billion, eleven million, two hundred ten thousand, forty-one".
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