Base | Representation |
---|---|
bin | 1001001101000011111110… |
… | …1011001000100101001011 |
3 | 1022211110111222111222002101 |
4 | 2103100333223020211023 |
5 | 2311301240333040243 |
6 | 33305022522014231 |
7 | 2063101212034033 |
oct | 223207753104513 |
9 | 38743458458071 |
10 | 10120011221323 |
11 | 3251966562963 |
12 | 11753ab347377 |
13 | 58540b771313 |
14 | 26db4db568c3 |
15 | 1283a0db354d |
hex | 9343fac894b |
10120011221323 has 2 divisors, whose sum is σ = 10120011221324. Its totient is φ = 10120011221322.
The previous prime is 10120011221273. The next prime is 10120011221351. The reversal of 10120011221323 is 32312211002101.
10120011221323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10120011221323 - 241 = 7920987965771 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 10120011221323.
It is not a weakly prime, because it can be changed into another prime (10120011621323) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060005610661 + 5060005610662.
It is an arithmetic number, because the mean of its divisors is an integer number (5060005610662).
Almost surely, 210120011221323 is an apocalyptic number.
10120011221323 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120011221323 is an equidigital number, since it uses as much as digits as its factorization.
10120011221323 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 10120011221323 its reverse (32312211002101), we get a palindrome (42432222223424).
The spelling of 10120011221323 in words is "ten trillion, one hundred twenty billion, eleven million, two hundred twenty-one thousand, three hundred twenty-three".
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