Search a number
-
+
10120033113 = 35363648007
BaseRepresentation
bin10010110110011001…
…10111001101011001
3222010021121221121020
421123030313031121
5131211212024423
64352111233053
7505532601501
oct113314671531
928107557536
1010120033113
114323549733
121b65218789
13c53826498
146c008aa01
153e36bd4e3
hex25b337359

10120033113 has 8 divisors (see below), whose sum is σ = 13747969728. Its totient is φ = 6619392624.

The previous prime is 10120033103. The next prime is 10120033117. The reversal of 10120033113 is 31133002101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10120033113 - 210 = 10120032089 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120033092 and 10120033101.

It is not an unprimeable number, because it can be changed into a prime (10120033117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 31823845 + ... + 31824162.

It is an arithmetic number, because the mean of its divisors is an integer number (1718496216).

Almost surely, 210120033113 is an apocalyptic number.

It is an amenable number.

10120033113 is a deficient number, since it is larger than the sum of its proper divisors (3627936615).

10120033113 is an equidigital number, since it uses as much as digits as its factorization.

10120033113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 63648063.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 10120033113 its reverse (31133002101), we get a palindrome (41253035214).

The spelling of 10120033113 in words is "ten billion, one hundred twenty million, thirty-three thousand, one hundred thirteen".

Divisors: 1 3 53 159 63648007 190944021 3373344371 10120033113