Base | Representation |
---|---|
bin | 1001001101000100010100… |
… | …0001101100000111011011 |
3 | 1022211110202020111012212212 |
4 | 2103101011001230013123 |
5 | 2311301431330120443 |
6 | 33305035450425335 |
7 | 2063103352231103 |
oct | 223210501540733 |
9 | 38743666435785 |
10 | 10120101020123 |
11 | 3251a02217046 |
12 | 117541543224b |
13 | 5854242527c3 |
14 | 26db5ba50203 |
15 | 1283a8c00618 |
hex | 9344506c1db |
10120101020123 has 2 divisors, whose sum is σ = 10120101020124. Its totient is φ = 10120101020122.
The previous prime is 10120101020111. The next prime is 10120101020131. The reversal of 10120101020123 is 32102010102101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 10120101020123 - 28 = 10120101019867 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 10120101020098 and 10120101020107.
It is not a weakly prime, because it can be changed into another prime (10120101020423) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060050510061 + 5060050510062.
It is an arithmetic number, because the mean of its divisors is an integer number (5060050510062).
Almost surely, 210120101020123 is an apocalyptic number.
10120101020123 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120101020123 is an equidigital number, since it uses as much as digits as its factorization.
10120101020123 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 10120101020123 its reverse (32102010102101), we get a palindrome (42222111122224).
The spelling of 10120101020123 in words is "ten trillion, one hundred twenty billion, one hundred one million, twenty thousand, one hundred twenty-three".
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