Base | Representation |
---|---|
bin | 111100010100100… |
… | …001001111100011 |
3 | 2121112021112111001 |
4 | 330110201033203 |
5 | 4033033341003 |
6 | 244230532431 |
7 | 34035650212 |
oct | 7424411743 |
9 | 2545245431 |
10 | 1012012003 |
11 | 47a288662 |
12 | 242b07117 |
13 | 131884792 |
14 | 98597079 |
15 | 5dca561d |
hex | 3c5213e3 |
1012012003 has 2 divisors, whose sum is σ = 1012012004. Its totient is φ = 1012012002.
The previous prime is 1012011971. The next prime is 1012012031. The reversal of 1012012003 is 3002102101.
1012012003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1012012003 - 25 = 1012011971 is a prime.
It is not a weakly prime, because it can be changed into another prime (1012012033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506006001 + 506006002.
It is an arithmetic number, because the mean of its divisors is an integer number (506006002).
Almost surely, 21012012003 is an apocalyptic number.
1012012003 is a deficient number, since it is larger than the sum of its proper divisors (1).
1012012003 is an equidigital number, since it uses as much as digits as its factorization.
1012012003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 10.
The square root of 1012012003 is about 31812.1360961505. The cubic root of 1012012003 is about 1003.9880751138.
Adding to 1012012003 its reverse (3002102101), we get a palindrome (4014114104).
The spelling of 1012012003 in words is "one billion, twelve million, twelve thousand, three".
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