101201311322131 has 4 divisors (see below), whose sum is σ = 101929378310200. Its totient is φ = 100473244334064.

The previous prime is 101201311322087. The next prime is 101201311322183. The reversal of 101201311322131 is 131223113102101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101201311322131 - 2¹³ = 101201311313939 is a prime.

It is a super-2 number, since 2×101201311322131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (101201311322231) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 364033493826 + ... + 364033494103.

It is an arithmetic number, because the mean of its divisors is an integer number (25482344577550).

Almost surely, 2^{101201311322131} is an apocalyptic number.

101201311322131 is a deficient number, since it is larger than the sum of its proper divisors (728066988069).

101201311322131 is an equidigital number, since it uses as much as digits as its factorization.

101201311322131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 728066988068.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 101201311322131 its reverse (131223113102101), we get a palindrome (232424424424232).

It can be divided in two parts, 1012013 and 11322131, that added together give a square (12334144 = 3512²).

The spelling of 101201311322131 in words is "one hundred one trillion, two hundred one billion, three hundred eleven million, three hundred twenty-two thousand, one hundred thirty-one".