10120144911137 has 2 divisors, whose sum is σ = 10120144911138. Its totient is φ = 10120144911136.

The previous prime is 10120144911077. The next prime is 10120144911223. The reversal of 10120144911137 is 73111944102101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10056484070416 + 63660840721 = 3171196^2 + 252311^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10120144911137 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 10120144911097 and 10120144911106.

It is not a weakly prime, because it can be changed into another prime (10120144911337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060072455568 + 5060072455569.

It is an arithmetic number, because the mean of its divisors is an integer number (5060072455569).

Almost surely, 2^{10120144911137} is an apocalyptic number.

It is an amenable number.

10120144911137 is a deficient number, since it is larger than the sum of its proper divisors (1).

10120144911137 is an equidigital number, since it uses as much as digits as its factorization.

10120144911137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 35.

The spelling of 10120144911137 in words is "ten trillion, one hundred twenty billion, one hundred forty-four million, nine hundred eleven thousand, one hundred thirty-seven".