Base | Representation |
---|---|
bin | 10010110110011010… |
… | …11100110111011001 |
3 | 222010021220210011211 |
4 | 21123031130313121 |
5 | 131211231443403 |
6 | 4352114423121 |
7 | 505534113253 |
oct | 113315346731 |
9 | 28107823154 |
10 | 10120187353 |
11 | 4323644601 |
12 | 1b65291aa1 |
13 | c5387b753 |
14 | 6c00cacd3 |
15 | 3e36ee06d |
hex | 25b35cdd9 |
10120187353 has 2 divisors, whose sum is σ = 10120187354. Its totient is φ = 10120187352.
The previous prime is 10120187347. The next prime is 10120187411. The reversal of 10120187353 is 35378102101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7076679129 + 3043508224 = 84123^2 + 55168^2 .
It is a cyclic number.
It is not a de Polignac number, because 10120187353 - 29 = 10120186841 is a prime.
It is a super-2 number, since 2×101201873532 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (10120187653) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5060093676 + 5060093677.
It is an arithmetic number, because the mean of its divisors is an integer number (5060093677).
Almost surely, 210120187353 is an apocalyptic number.
It is an amenable number.
10120187353 is a deficient number, since it is larger than the sum of its proper divisors (1).
10120187353 is an equidigital number, since it uses as much as digits as its factorization.
10120187353 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5040, while the sum is 31.
Adding to 10120187353 its reverse (35378102101), we get a palindrome (45498289454).
The spelling of 10120187353 in words is "ten billion, one hundred twenty million, one hundred eighty-seven thousand, three hundred fifty-three".
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