101202220033 has 4 divisors (see below), whose sum is σ = 104466807808. Its totient is φ = 97937632260.

The previous prime is 101202220019. The next prime is 101202220037. The reversal of 101202220033 is 330022202101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 330022202101 = 7949 ⋅41517449.

It is not a de Polignac number, because 101202220033 - 2⁵ = 101202220001 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101202219989 and 101202220016.

It is not an unprimeable number, because it can be changed into a prime (101202220037) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1632293841 + ... + 1632293902.

It is an arithmetic number, because the mean of its divisors is an integer number (26116701952).

Almost surely, 2^101202220033 is an apocalyptic number.

It is an amenable number.

101202220033 is a deficient number, since it is larger than the sum of its proper divisors (3264587775).

101202220033 is an equidigital number, since it uses as much as digits as its factorization.

101202220033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3264587774.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 101202220033 its reverse (330022202101), we get a palindrome (431224422134).

The spelling of 101202220033 in words is "one hundred one billion, two hundred two million, two hundred twenty thousand, thirty-three".