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1012135224481 is a prime number
BaseRepresentation
bin11101011101001111111…
…01011110010010100001
310120202111102222200221121
432232213331132102201
5113040323104140411
62052545110252241
7133060440313153
oct16564775362241
93522442880847
101012135224481
11360275a47737
121441aa057081
13745a0457b44
1436db7dc4ad3
151b4dbce8571
hexeba7f5e4a1

1012135224481 has 2 divisors, whose sum is σ = 1012135224482. Its totient is φ = 1012135224480.

The previous prime is 1012135224389. The next prime is 1012135224509. The reversal of 1012135224481 is 1844225312101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 842898429025 + 169236795456 = 918095^2 + 411384^2 .

It is an emirp because it is prime and its reverse (1844225312101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1012135224481 - 215 = 1012135191713 is a prime.

It is a super-2 number, since 2×10121352244812 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1012135204481) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506067612240 + 506067612241.

It is an arithmetic number, because the mean of its divisors is an integer number (506067612241).

Almost surely, 21012135224481 is an apocalyptic number.

It is an amenable number.

1012135224481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1012135224481 is an equidigital number, since it uses as much as digits as its factorization.

1012135224481 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15360, while the sum is 34.

The spelling of 1012135224481 in words is "one trillion, twelve billion, one hundred thirty-five million, two hundred twenty-four thousand, four hundred eighty-one".