Base | Representation |
---|---|
bin | 101111001000100101… |
… | …1101010010101111011 |
3 | 100200021012021211012101 |
4 | 1132101023222111323 |
5 | 3124244310014042 |
6 | 114255543524231 |
7 | 10212216546106 |
oct | 1362113522573 |
9 | 320235254171 |
10 | 101220001147 |
11 | 39a22063011 |
12 | 1774a459677 |
13 | 97114b7a05 |
14 | 4c830b973d |
15 | 29763c66b7 |
hex | 17912ea57b |
101220001147 has 2 divisors, whose sum is σ = 101220001148. Its totient is φ = 101220001146.
The previous prime is 101220001109. The next prime is 101220001151. The reversal of 101220001147 is 741100022101.
It is a strong prime.
It is an emirp because it is prime and its reverse (741100022101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 101220001147 - 211 = 101219999099 is a prime.
It is not a weakly prime, because it can be changed into another prime (101220011147) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610000573 + 50610000574.
It is an arithmetic number, because the mean of its divisors is an integer number (50610000574).
Almost surely, 2101220001147 is an apocalyptic number.
101220001147 is a deficient number, since it is larger than the sum of its proper divisors (1).
101220001147 is an equidigital number, since it uses as much as digits as its factorization.
101220001147 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 112, while the sum is 19.
Adding to 101220001147 its reverse (741100022101), we get a palindrome (842320023248).
The spelling of 101220001147 in words is "one hundred one billion, two hundred twenty million, one thousand, one hundred forty-seven".
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