10122023003113 has 4 divisors (see below), whose sum is σ = 11568026289280. Its totient is φ = 8676019716948.

The previous prime is 10122023003063. The next prime is 10122023003117. The reversal of 10122023003113 is 31130032022101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-10122023003113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10122023003117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723001643073 + ... + 723001643086.

It is an arithmetic number, because the mean of its divisors is an integer number (2892006572320).

Almost surely, 2^{10122023003113} is an apocalyptic number.

It is an amenable number.

10122023003113 is a deficient number, since it is larger than the sum of its proper divisors (1446003286167).

10122023003113 is an equidigital number, since it uses as much as digits as its factorization.

10122023003113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1446003286166.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 10122023003113 its reverse (31130032022101), we get a palindrome (41252055025214).

The spelling of 10122023003113 in words is "ten trillion, one hundred twenty-two billion, twenty-three million, three thousand, one hundred thirteen".