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101221100051 is a prime number
BaseRepresentation
bin101111001000100111…
…1110110101000010011
3100200021021100122121112
41132101033312220103
53124300100200201
6114300023243535
710212232103651
oct1362117665023
9320237318545
10101221100051
1139a227436a5
121774a8a95ab
1397117b0c56
144c832c3dd1
1529765420bb
hex17913f6a13

101221100051 has 2 divisors, whose sum is σ = 101221100052. Its totient is φ = 101221100050.

The previous prime is 101221100041. The next prime is 101221100077. The reversal of 101221100051 is 150001122101.

It is a weak prime.

It is an emirp because it is prime and its reverse (150001122101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101221100051 is a prime.

It is a super-2 number, since 2×1012211000512 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101221099999 and 101221100035.

It is not a weakly prime, because it can be changed into another prime (101221100041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610550025 + 50610550026.

It is an arithmetic number, because the mean of its divisors is an integer number (50610550026).

Almost surely, 2101221100051 is an apocalyptic number.

101221100051 is a deficient number, since it is larger than the sum of its proper divisors (1).

101221100051 is an equidigital number, since it uses as much as digits as its factorization.

101221100051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20, while the sum is 14.

Adding to 101221100051 its reverse (150001122101), we get a palindrome (251222222152).

The spelling of 101221100051 in words is "one hundred one billion, two hundred twenty-one million, one hundred thousand, fifty-one".