Base | Representation |
---|---|
bin | 101111001000100111… |
… | …1110110101000010011 |
3 | 100200021021100122121112 |
4 | 1132101033312220103 |
5 | 3124300100200201 |
6 | 114300023243535 |
7 | 10212232103651 |
oct | 1362117665023 |
9 | 320237318545 |
10 | 101221100051 |
11 | 39a227436a5 |
12 | 1774a8a95ab |
13 | 97117b0c56 |
14 | 4c832c3dd1 |
15 | 29765420bb |
hex | 17913f6a13 |
101221100051 has 2 divisors, whose sum is σ = 101221100052. Its totient is φ = 101221100050.
The previous prime is 101221100041. The next prime is 101221100077. The reversal of 101221100051 is 150001122101.
It is a weak prime.
It is an emirp because it is prime and its reverse (150001122101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101221100051 is a prime.
It is a super-2 number, since 2×1012211000512 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 101221099999 and 101221100035.
It is not a weakly prime, because it can be changed into another prime (101221100041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50610550025 + 50610550026.
It is an arithmetic number, because the mean of its divisors is an integer number (50610550026).
Almost surely, 2101221100051 is an apocalyptic number.
101221100051 is a deficient number, since it is larger than the sum of its proper divisors (1).
101221100051 is an equidigital number, since it uses as much as digits as its factorization.
101221100051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20, while the sum is 14.
Adding to 101221100051 its reverse (150001122101), we get a palindrome (251222222152).
The spelling of 101221100051 in words is "one hundred one billion, two hundred twenty-one million, one hundred thousand, fifty-one".
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