101222100131 has 2 divisors, whose sum is σ = 101222100132. Its totient is φ = 101222100130.

The previous prime is 101222100101. The next prime is 101222100137. The reversal of 101222100131 is 131001222101.

It is a strong prime.

It is an emirp because it is prime and its reverse (131001222101) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-101222100131 is a prime.

It is a super-2 number, since 2×101222100131² (a number of 23 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101222100137) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611050065 + 50611050066.

It is an arithmetic number, because the mean of its divisors is an integer number (50611050066).

Almost surely, 2^101222100131 is an apocalyptic number.

101222100131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101222100131 is an equidigital number, since it uses as much as digits as its factorization.

101222100131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 14.

Adding to 101222100131 its reverse (131001222101), we get a palindrome (232223322232).

The spelling of 101222100131 in words is "one hundred one billion, two hundred twenty-two million, one hundred thousand, one hundred thirty-one".