Base | Representation |
---|---|
bin | 11101011101011010010… |
… | …01010101101110011011 |
3 | 10120202201111200121000201 |
4 | 32232231021111232123 |
5 | 113041012342034321 |
6 | 2053001455043031 |
7 | 133062544630015 |
oct | 16565511255633 |
9 | 3522644617021 |
10 | 1012222221211 |
11 | 360310067663 |
12 | 144213210477 |
13 | 745b5497ab6 |
14 | 36dc578d1b5 |
15 | 1b4e4780291 |
hex | ebad255b9b |
1012222221211 has 4 divisors (see below), whose sum is σ = 1025035160800. Its totient is φ = 999409281624.
The previous prime is 1012222221203. The next prime is 1012222221221. The reversal of 1012222221211 is 1121222222101.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1012222221211 - 23 = 1012222221203 is a prime.
It is a super-2 number, since 2×10122222212112 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1012222221221) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6406469676 + ... + 6406469833.
It is an arithmetic number, because the mean of its divisors is an integer number (256258790200).
Almost surely, 21012222221211 is an apocalyptic number.
1012222221211 is a deficient number, since it is larger than the sum of its proper divisors (12812939589).
1012222221211 is an equidigital number, since it uses as much as digits as its factorization.
1012222221211 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12812939588.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 1012222221211 its reverse (1121222222101), we get a palindrome (2133444443312).
The spelling of 1012222221211 in words is "one trillion, twelve billion, two hundred twenty-two million, two hundred twenty-one thousand, two hundred eleven".
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