Search a number
-
+
101223230120273 is a prime number
BaseRepresentation
bin10111000000111111011110…
…101011001010000101010001
3111021101211211221121000112002
4113000333132223022011101
5101231420133402322043
6555141150541243345
730215065001461412
oct2700773653120521
9437354757530462
10101223230120273
112a286592578478
12b4298a6b63555
134463404391a41
141add33260b809
15ba80adac3bb8
hex5c0fdeaca151

101223230120273 has 2 divisors, whose sum is σ = 101223230120274. Its totient is φ = 101223230120272.

The previous prime is 101223230120197. The next prime is 101223230120321. The reversal of 101223230120273 is 372021032322101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 61808025028864 + 39415205091409 = 7861808^2 + 6278153^2 .

It is a cyclic number.

It is not a de Polignac number, because 101223230120273 - 214 = 101223230103889 is a prime.

It is a super-2 number, since 2×1012232301202732 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (101223230123273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50611615060136 + 50611615060137.

It is an arithmetic number, because the mean of its divisors is an integer number (50611615060137).

Almost surely, 2101223230120273 is an apocalyptic number.

It is an amenable number.

101223230120273 is a deficient number, since it is larger than the sum of its proper divisors (1).

101223230120273 is an equidigital number, since it uses as much as digits as its factorization.

101223230120273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 101223230120273 its reverse (372021032322101), we get a palindrome (473244262442374).

The spelling of 101223230120273 in words is "one hundred one trillion, two hundred twenty-three billion, two hundred thirty million, one hundred twenty thousand, two hundred seventy-three".