Base | Representation |
---|---|
bin | 10010110110101011… |
… | …11100100000100001 |
3 | 222010110002220201102 |
4 | 21123111330200201 |
5 | 131212314222423 |
6 | 4352234244145 |
7 | 505562046260 |
oct | 113325744041 |
9 | 28113086642 |
10 | 10122414113 |
11 | 43249255a9 |
12 | 1b65b86655 |
13 | c5417b166 |
14 | 6c050a5d7 |
15 | 3e39ddc28 |
hex | 25b57c821 |
10122414113 has 4 divisors (see below), whose sum is σ = 11568473280. Its totient is φ = 8676354948.
The previous prime is 10122414089. The next prime is 10122414143. The reversal of 10122414113 is 31141422101.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 10122414113 - 212 = 10122410017 is a prime.
It is not an unprimeable number, because it can be changed into a prime (10122414143) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 723029573 + ... + 723029586.
It is an arithmetic number, because the mean of its divisors is an integer number (2892118320).
Almost surely, 210122414113 is an apocalyptic number.
It is an amenable number.
10122414113 is a deficient number, since it is larger than the sum of its proper divisors (1446059167).
10122414113 is an equidigital number, since it uses as much as digits as its factorization.
10122414113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1446059166.
The product of its (nonzero) digits is 192, while the sum is 20.
Adding to 10122414113 its reverse (31141422101), we get a palindrome (41263836214).
The spelling of 10122414113 in words is "ten billion, one hundred twenty-two million, four hundred fourteen thousand, one hundred thirteen".
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