1012354013113 has 4 divisors (see below), whose sum is σ = 1021815265680. Its totient is φ = 1002892760548.

The previous prime is 1012354013057. The next prime is 1012354013129. The reversal of 1012354013113 is 3113104532101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1012354013113 - 2⁹ = 1012354012601 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1012354413113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4730626123 + ... + 4730626336.

It is an arithmetic number, because the mean of its divisors is an integer number (255453816420).

Almost surely, 2^{1012354013113} is an apocalyptic number.

It is an amenable number.

1012354013113 is a deficient number, since it is larger than the sum of its proper divisors (9461252567).

1012354013113 is an equidigital number, since it uses as much as digits as its factorization.

1012354013113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9461252566.

The product of its (nonzero) digits is 1080, while the sum is 25.

Adding to 1012354013113 its reverse (3113104532101), we get a palindrome (4125458545214).

The spelling of 1012354013113 in words is "one trillion, twelve billion, three hundred fifty-four million, thirteen thousand, one hundred thirteen".