Search a number
-
+
10130011122169 is a prime number
BaseRepresentation
bin1001001101101001001110…
…1101101110100111111001
31022212102022220002120012101
42103122103231232213321
52311432230321402134
633313355102343401
72063604055553641
oct223322355564771
938772286076171
1010130011122169
11325612820a424
12117732028ab61
13586343425603
1427041bc91521
15128788c51e14
hex93693b6e9f9

10130011122169 has 2 divisors, whose sum is σ = 10130011122170. Its totient is φ = 10130011122168.

The previous prime is 10130011122131. The next prime is 10130011122173. The reversal of 10130011122169 is 96122111003101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5485727518569 + 4644283603600 = 2342163^2 + 2155060^2 .

It is an emirp because it is prime and its reverse (96122111003101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10130011122169 - 223 = 10130002733561 is a prime.

It is a super-2 number, since 2×101300111221692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10130011122269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065005561084 + 5065005561085.

It is an arithmetic number, because the mean of its divisors is an integer number (5065005561085).

Almost surely, 210130011122169 is an apocalyptic number.

It is an amenable number.

10130011122169 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130011122169 is an equidigital number, since it uses as much as digits as its factorization.

10130011122169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 28.

The spelling of 10130011122169 in words is "ten trillion, one hundred thirty billion, eleven million, one hundred twenty-two thousand, one hundred sixty-nine".