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10130022328193 is a prime number
BaseRepresentation
bin1001001101101001010001…
…1000011110011110000001
31022212102100200011212222022
42103122110120132132001
52311432241204000233
633313400142451225
72063604253035365
oct223322430363601
938772320155868
1010130022328193
1132561335736a9
121177323b93b15
1358634584a0b1
1427041d56b2a5
15128789c17398
hex9369461e781

10130022328193 has 2 divisors, whose sum is σ = 10130022328194. Its totient is φ = 10130022328192.

The previous prime is 10130022328183. The next prime is 10130022328201. The reversal of 10130022328193 is 39182322003101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8547337557889 + 1582684770304 = 2923583^2 + 1258048^2 .

It is an emirp because it is prime and its reverse (39182322003101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 10130022328193 - 230 = 10128948586369 is a prime.

It is not a weakly prime, because it can be changed into another prime (10130022328183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065011164096 + 5065011164097.

It is an arithmetic number, because the mean of its divisors is an integer number (5065011164097).

Almost surely, 210130022328193 is an apocalyptic number.

It is an amenable number.

10130022328193 is a deficient number, since it is larger than the sum of its proper divisors (1).

10130022328193 is an equidigital number, since it uses as much as digits as its factorization.

10130022328193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 35.

The spelling of 10130022328193 in words is "ten trillion, one hundred thirty billion, twenty-two million, three hundred twenty-eight thousand, one hundred ninety-three".