Base | Representation |
---|---|
bin | 11101011110110111100… |
… | …00011001111100011001 |
3 | 10120211202000010221112010 |
4 | 32233123300121330121 |
5 | 113044113034322131 |
6 | 2053211231540133 |
7 | 133121121514341 |
oct | 16573360317431 |
9 | 3524660127463 |
10 | 1013004214041 |
11 | 360681519426 |
12 | 1443b108a649 |
13 | 746ab4b4651 |
14 | 3705b58bd21 |
15 | 1b53d24bb46 |
hex | ebdbc19f19 |
1013004214041 has 8 divisors (see below), whose sum is σ = 1352759880384. Its totient is φ = 674292345200.
The previous prime is 1013004214031. The next prime is 1013004214049. The reversal of 1013004214041 is 1404124003101.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1013004214041 - 27 = 1013004213913 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1013004213999 and 1013004214017.
It is not an unprimeable number, because it can be changed into a prime (1013004214049) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 260947110 + ... + 260950991.
It is an arithmetic number, because the mean of its divisors is an integer number (169094985048).
Almost surely, 21013004214041 is an apocalyptic number.
It is an amenable number.
1013004214041 is a deficient number, since it is larger than the sum of its proper divisors (339755666343).
1013004214041 is an equidigital number, since it uses as much as digits as its factorization.
1013004214041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 521898751.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 1013004214041 its reverse (1404124003101), we get a palindrome (2417128217142).
The spelling of 1013004214041 in words is "one trillion, thirteen billion, four million, two hundred fourteen thousand, forty-one".
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