Base | Representation |
---|---|
bin | 10010110111100110… |
… | …10100001000001001 |
3 | 222010222121001122121 |
4 | 21123303110020021 |
5 | 131221302104113 |
6 | 4353111251241 |
7 | 506014353145 |
oct | 113363241011 |
9 | 28128531577 |
10 | 10130113033 |
11 | 4329203947 |
12 | 1b68679b21 |
13 | c55945531 |
14 | 6c1552225 |
15 | 3e450ee8d |
hex | 25bcd4209 |
10130113033 has 2 divisors, whose sum is σ = 10130113034. Its totient is φ = 10130113032.
The previous prime is 10130113003. The next prime is 10130113067. The reversal of 10130113033 is 33031103101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6801630784 + 3328482249 = 82472^2 + 57693^2 .
It is a cyclic number.
It is not a de Polignac number, because 10130113033 - 213 = 10130104841 is a prime.
It is a super-2 number, since 2×101301130332 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 10130112998 and 10130113016.
It is not a weakly prime, because it can be changed into another prime (10130113003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065056516 + 5065056517.
It is an arithmetic number, because the mean of its divisors is an integer number (5065056517).
Almost surely, 210130113033 is an apocalyptic number.
It is an amenable number.
10130113033 is a deficient number, since it is larger than the sum of its proper divisors (1).
10130113033 is an equidigital number, since it uses as much as digits as its factorization.
10130113033 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 10130113033 its reverse (33031103101), we get a palindrome (43161216134).
The spelling of 10130113033 in words is "ten billion, one hundred thirty million, one hundred thirteen thousand, thirty-three".
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