10131042130081 has 2 divisors, whose sum is σ = 10131042130082. Its totient is φ = 10131042130080.

The previous prime is 10131042130043. The next prime is 10131042130169. The reversal of 10131042130081 is 18003124013101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6938087700625 + 3192954429456 = 2634025^2 + 1786884^2 .

It is a cyclic number.

It is not a de Polignac number, because 10131042130081 - 2⁴¹ = 7932018874529 is a prime.

It is a super-2 number, since 2×10131042130081² (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (10131042130981) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5065521065040 + 5065521065041.

It is an arithmetic number, because the mean of its divisors is an integer number (5065521065041).

Almost surely, 2^{10131042130081} is an apocalyptic number.

It is an amenable number.

10131042130081 is a deficient number, since it is larger than the sum of its proper divisors (1).

10131042130081 is an equidigital number, since it uses as much as digits as its factorization.

10131042130081 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 10131042130081 its reverse (18003124013101), we get a palindrome (28134166143182).

The spelling of 10131042130081 in words is "ten trillion, one hundred thirty-one billion, forty-two million, one hundred thirty thousand, eighty-one".