Search a number
-
+
10131314433 = 33791273103
BaseRepresentation
bin10010110111101111…
…11001011100000001
3222011001212002122220
421123313321130001
5131222104030213
64353153121253
7506030515602
oct113367713401
928131762586
1010131314433
114329954539
121b68b59229
13c55c76316
146c1785da9
153e469ae23
hex25bdf9701

10131314433 has 8 divisors (see below), whose sum is σ = 13873511808. Its totient is φ = 6571663344.

The previous prime is 10131314423. The next prime is 10131314447. The reversal of 10131314433 is 33441313101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 10131314433 - 218 = 10131052289 is a prime.

It is a super-2 number, since 2×101313144332 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (10131314423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 45636441 + ... + 45636662.

It is an arithmetic number, because the mean of its divisors is an integer number (1734188976).

Almost surely, 210131314433 is an apocalyptic number.

It is an amenable number.

10131314433 is a deficient number, since it is larger than the sum of its proper divisors (3742197375).

10131314433 is an equidigital number, since it uses as much as digits as its factorization.

10131314433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 91273143.

The product of its (nonzero) digits is 1296, while the sum is 24.

Adding to 10131314433 its reverse (33441313101), we get a palindrome (43572627534).

The spelling of 10131314433 in words is "ten billion, one hundred thirty-one million, three hundred fourteen thousand, four hundred thirty-three".

Divisors: 1 3 37 111 91273103 273819309 3377104811 10131314433