101320055113 has 2 divisors, whose sum is σ = 101320055114. Its totient is φ = 101320055112.

The previous prime is 101320055099. The next prime is 101320055159. The reversal of 101320055113 is 311550023101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 97945839369 + 3374215744 = 312963^2 + 58088^2 .

It is a cyclic number.

It is not a de Polignac number, because 101320055113 - 2¹³ = 101320046921 is a prime.

It is not a weakly prime, because it can be changed into another prime (101320005113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660027556 + 50660027557.

It is an arithmetic number, because the mean of its divisors is an integer number (50660027557).

Almost surely, 2^101320055113 is an apocalyptic number.

It is an amenable number.

101320055113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101320055113 is an equidigital number, since it uses as much as digits as its factorization.

101320055113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 450, while the sum is 22.

Adding to 101320055113 its reverse (311550023101), we get a palindrome (412870078214).

The spelling of 101320055113 in words is "one hundred one billion, three hundred twenty million, fifty-five thousand, one hundred thirteen".