Base | Representation |
---|---|
bin | 111100011001000… |
… | …011110001100011 |
3 | 2121121111222212201 |
4 | 330121003301203 |
5 | 4033334431034 |
6 | 244312234031 |
7 | 34052034514 |
oct | 7431036143 |
9 | 2547458781 |
10 | 1013202019 |
11 | 47aa20745 |
12 | 24339b917 |
13 | 131bb032b |
14 | 987c6a0b |
15 | 5de3d014 |
hex | 3c643c63 |
1013202019 has 2 divisors, whose sum is σ = 1013202020. Its totient is φ = 1013202018.
The previous prime is 1013201953. The next prime is 1013202079. The reversal of 1013202019 is 9102023101.
1013202019 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1013202019 - 227 = 878984291 is a prime.
It is a super-2 number, since 2×10132020192 = 2053156662611352722, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1013201987 and 1013202005.
It is not a weakly prime, because it can be changed into another prime (1013202079) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506601009 + 506601010.
It is an arithmetic number, because the mean of its divisors is an integer number (506601010).
Almost surely, 21013202019 is an apocalyptic number.
1013202019 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013202019 is an equidigital number, since it uses as much as digits as its factorization.
1013202019 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108, while the sum is 19.
The square root of 1013202019 is about 31830.8344062797. The cubic root of 1013202019 is about 1004.3814478775.
The spelling of 1013202019 in words is "one billion, thirteen million, two hundred two thousand, nineteen".
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