Base | Representation |
---|---|
bin | 10010110111110101… |
… | …01000001100111011 |
3 | 222011010012110121021 |
4 | 21123322220030323 |
5 | 131222244432032 |
6 | 4353220323311 |
7 | 506036556562 |
oct | 113372501473 |
9 | 28133173537 |
10 | 10132030267 |
11 | 432a2a3337 |
12 | 1b69243537 |
13 | c561670a8 |
14 | 6c18d0bd9 |
15 | 3e478d097 |
hex | 25bea833b |
10132030267 has 2 divisors, whose sum is σ = 10132030268. Its totient is φ = 10132030266.
The previous prime is 10132030201. The next prime is 10132030283. The reversal of 10132030267 is 76203023101.
It is a strong prime.
It is an emirp because it is prime and its reverse (76203023101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10132030267 - 211 = 10132028219 is a prime.
It is a super-3 number, since 3×101320302673 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (10132030367) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066015133 + 5066015134.
It is an arithmetic number, because the mean of its divisors is an integer number (5066015134).
Almost surely, 210132030267 is an apocalyptic number.
10132030267 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132030267 is an equidigital number, since it uses as much as digits as its factorization.
10132030267 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 10132030267 its reverse (76203023101), we get a palindrome (86335053368).
The spelling of 10132030267 in words is "ten billion, one hundred thirty-two million, thirty thousand, two hundred sixty-seven".
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