Base | Representation |
---|---|
bin | 10111000010011001111000… |
… | …101011001110110001001011 |
3 | 111021202010102010112220012221 |
4 | 113002121320223032301023 |
5 | 101240012440044024433 |
6 | 555253523224314511 |
7 | 30225102364336036 |
oct | 2702317053166113 |
9 | 437663363486187 |
10 | 101320303111243 |
11 | 2a313776767347 |
12 | b444678612a37 |
13 | 446c604664c78 |
14 | 1b03d00a2601d |
15 | baa890d8672d |
hex | 5c2678acec4b |
101320303111243 has 2 divisors, whose sum is σ = 101320303111244. Its totient is φ = 101320303111242.
The previous prime is 101320303111231. The next prime is 101320303111253. The reversal of 101320303111243 is 342111303023101.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 101320303111243 - 221 = 101320301014091 is a prime.
It is not a weakly prime, because it can be changed into another prime (101320303111213) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660151555621 + 50660151555622.
It is an arithmetic number, because the mean of its divisors is an integer number (50660151555622).
Almost surely, 2101320303111243 is an apocalyptic number.
101320303111243 is a deficient number, since it is larger than the sum of its proper divisors (1).
101320303111243 is an equidigital number, since it uses as much as digits as its factorization.
101320303111243 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 101320303111243 its reverse (342111303023101), we get a palindrome (443431606134344).
The spelling of 101320303111243 in words is "one hundred one trillion, three hundred twenty billion, three hundred three million, one hundred eleven thousand, two hundred forty-three".
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