Base | Representation |
---|---|
bin | 10111000010011001111010… |
… | …010010100111011100010011 |
3 | 111021202010111000112211000212 |
4 | 113002121322102213130103 |
5 | 101240013014013310024 |
6 | 555253530033234335 |
7 | 30225103143604232 |
oct | 2702317222473423 |
9 | 437663430484025 |
10 | 101320330213139 |
11 | 2a31378aa98404 |
12 | b4446857029ab |
13 | 446c60a163aab |
14 | 1b03d0447cb19 |
15 | baa89343ba0e |
hex | 5c267a4a7713 |
101320330213139 has 2 divisors, whose sum is σ = 101320330213140. Its totient is φ = 101320330213138.
The previous prime is 101320330213127. The next prime is 101320330213159. The reversal of 101320330213139 is 931312033023101.
It is a weak prime.
It is an emirp because it is prime and its reverse (931312033023101) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-101320330213139 is a prime.
It is not a weakly prime, because it can be changed into another prime (101320330213159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660165106569 + 50660165106570.
It is an arithmetic number, because the mean of its divisors is an integer number (50660165106570).
Almost surely, 2101320330213139 is an apocalyptic number.
101320330213139 is a deficient number, since it is larger than the sum of its proper divisors (1).
101320330213139 is an equidigital number, since it uses as much as digits as its factorization.
101320330213139 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8748, while the sum is 32.
The spelling of 101320330213139 in words is "one hundred one trillion, three hundred twenty billion, three hundred thirty million, two hundred thirteen thousand, one hundred thirty-nine".
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