101321100131131 has 4 divisors (see below), whose sum is σ = 101321705536672. Its totient is φ = 101320494725592.

The previous prime is 101321100131129. The next prime is 101321100131143. The reversal of 101321100131131 is 131131001123101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 101321100131131 - 2¹ = 101321100131129 is a prime.

It is a super-2 number, since 2×101321100131131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 101321100131099 and 101321100131108.

It is not an unprimeable number, because it can be changed into a prime (101321100131171) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 302451660 + ... + 302786473.

It is an arithmetic number, because the mean of its divisors is an integer number (25330426384168).

Almost surely, 2^{101321100131131} is an apocalyptic number.

101321100131131 is a deficient number, since it is larger than the sum of its proper divisors (605405541).

101321100131131 is an equidigital number, since it uses as much as digits as its factorization.

101321100131131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 605405540.

The product of its (nonzero) digits is 54, while the sum is 19.

Adding to 101321100131131 its reverse (131131001123101), we get a palindrome (232452101254232).

The spelling of 101321100131131 in words is "one hundred one trillion, three hundred twenty-one billion, one hundred million, one hundred thirty-one thousand, one hundred thirty-one".