Base | Representation |
---|---|
bin | 10010110111110110… |
… | …00001010011011011 |
3 | 222011010101200122021 |
4 | 21123323001103123 |
5 | 131222311224313 |
6 | 4353222435311 |
7 | 506040465412 |
oct | 113373012333 |
9 | 28133350567 |
10 | 10132133083 |
11 | 432a363606 |
12 | 1b69292b37 |
13 | c561a1b27 |
14 | 6c191a479 |
15 | 3e47ad78d |
hex | 25bec14db |
10132133083 has 2 divisors, whose sum is σ = 10132133084. Its totient is φ = 10132133082.
The previous prime is 10132133051. The next prime is 10132133111. The reversal of 10132133083 is 38033123101.
10132133083 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (38033123101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10132133083 - 25 = 10132133051 is a prime.
It is not a weakly prime, because it can be changed into another prime (10132133183) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066066541 + 5066066542.
It is an arithmetic number, because the mean of its divisors is an integer number (5066066542).
Almost surely, 210132133083 is an apocalyptic number.
10132133083 is a deficient number, since it is larger than the sum of its proper divisors (1).
10132133083 is an equidigital number, since it uses as much as digits as its factorization.
10132133083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 10132133083 its reverse (38033123101), we get a palindrome (48165256184).
The spelling of 10132133083 in words is "ten billion, one hundred thirty-two million, one hundred thirty-three thousand, eighty-three".
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