101321444131 has 2 divisors, whose sum is σ = 101321444132. Its totient is φ = 101321444130.

The previous prime is 101321444101. The next prime is 101321444171. The reversal of 101321444131 is 131444123101.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 101321444131 - 2²⁵ = 101287889699 is a prime.

It is a super-2 number, since 2×101321444131² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 101321444096 and 101321444105.

It is not a weakly prime, because it can be changed into another prime (101321444101) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50660722065 + 50660722066.

It is an arithmetic number, because the mean of its divisors is an integer number (50660722066).

Almost surely, 2^101321444131 is an apocalyptic number.

101321444131 is a deficient number, since it is larger than the sum of its proper divisors (1).

101321444131 is an equidigital number, since it uses as much as digits as its factorization.

101321444131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 101321444131 its reverse (131444123101), we get a palindrome (232765567232).

The spelling of 101321444131 in words is "one hundred one billion, three hundred twenty-one million, four hundred forty-four thousand, one hundred thirty-one".