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10132545883 = 53191180111
BaseRepresentation
bin10010110111111001…
…00110000101011011
3222011011011122220011
421123330212011123
5131222412432013
64353235342351
7506044135045
oct113374460533
928134148804
1010132545883
11432a615769
121b694519b7
13c562b79a5
146c19c6a95
153e4840c3d
hex25bf2615b

10132545883 has 4 divisors (see below), whose sum is σ = 10323726048. Its totient is φ = 9941365720.

The previous prime is 10132545877. The next prime is 10132545923. The reversal of 10132545883 is 38854523101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10132545883 - 217 = 10132414811 is a prime.

It is a super-2 number, since 2×101325458832 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10132545383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95590003 + ... + 95590108.

It is an arithmetic number, because the mean of its divisors is an integer number (2580931512).

Almost surely, 210132545883 is an apocalyptic number.

10132545883 is a deficient number, since it is larger than the sum of its proper divisors (191180165).

10132545883 is an equidigital number, since it uses as much as digits as its factorization.

10132545883 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 191180164.

The product of its (nonzero) digits is 115200, while the sum is 40.

The spelling of 10132545883 in words is "ten billion, one hundred thirty-two million, five hundred forty-five thousand, eight hundred eighty-three".

Divisors: 1 53 191180111 10132545883