Base | Representation |
---|---|
bin | 10010110111111100… |
… | …10111111101111011 |
3 | 222011012001100202121 |
4 | 21123332113331323 |
5 | 131223022343342 |
6 | 4353253342111 |
7 | 506051120023 |
oct | 113376277573 |
9 | 28135040677 |
10 | 10133012347 |
11 | 432a904177 |
12 | 1b69637937 |
13 | c5641c0c3 |
14 | 6c1aa8a83 |
15 | 3e48d4067 |
hex | 25bf97f7b |
10133012347 has 2 divisors, whose sum is σ = 10133012348. Its totient is φ = 10133012346.
The previous prime is 10133012327. The next prime is 10133012371. The reversal of 10133012347 is 74321033101.
10133012347 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 10133012347 - 211 = 10133010299 is a prime.
It is not a weakly prime, because it can be changed into another prime (10133012327) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5066506173 + 5066506174.
It is an arithmetic number, because the mean of its divisors is an integer number (5066506174).
Almost surely, 210133012347 is an apocalyptic number.
10133012347 is a deficient number, since it is larger than the sum of its proper divisors (1).
10133012347 is an equidigital number, since it uses as much as digits as its factorization.
10133012347 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1512, while the sum is 25.
Adding to 10133012347 its reverse (74321033101), we get a palindrome (84454045448).
The spelling of 10133012347 in words is "ten billion, one hundred thirty-three million, twelve thousand, three hundred forty-seven".
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