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101330441131433 is a prime number
BaseRepresentation
bin10111000010100011010100…
…111100101101010110101001
3111021210002120200000200110012
4113002203110330231112221
5101240144220412201213
6555302321221301305
730225611536154153
oct2702432474552651
9437702520020405
10101330441131433
112a317aa9380a28
12b446627864835
13447055bb18597
141b045c3235ad3
15baac85e094a8
hex5c28d4f2d5a9

101330441131433 has 2 divisors, whose sum is σ = 101330441131434. Its totient is φ = 101330441131432.

The previous prime is 101330441131379. The next prime is 101330441131453. The reversal of 101330441131433 is 334131144033101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 97939584052249 + 3390857079184 = 9896443^2 + 1841428^2 .

It is a cyclic number.

It is not a de Polignac number, because 101330441131433 - 216 = 101330441065897 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 101330441131433.

It is not a weakly prime, because it can be changed into another prime (101330441131453) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50665220565716 + 50665220565717.

It is an arithmetic number, because the mean of its divisors is an integer number (50665220565717).

Almost surely, 2101330441131433 is an apocalyptic number.

It is an amenable number.

101330441131433 is a deficient number, since it is larger than the sum of its proper divisors (1).

101330441131433 is an equidigital number, since it uses as much as digits as its factorization.

101330441131433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 32.

Adding to 101330441131433 its reverse (334131144033101), we get a palindrome (435461585164534).

The spelling of 101330441131433 in words is "one hundred one trillion, three hundred thirty billion, four hundred forty-one million, one hundred thirty-one thousand, four hundred thirty-three".