Base | Representation |
---|---|
bin | 11101011111011110011… |
… | …11110011110001111001 |
3 | 10120212120210110020100201 |
4 | 32233233033303301321 |
5 | 113100300242312213 |
6 | 2053303512402201 |
7 | 133132202124340 |
oct | 16575717636171 |
9 | 3525523406321 |
10 | 1013331213433 |
11 | 36082a063960 |
12 | 1444826a6361 |
13 | 74731176706 |
14 | 3708cb8cb57 |
15 | 1b55bce06dd |
hex | ebef3f3c79 |
1013331213433 has 16 divisors (see below), whose sum is σ = 1274964577920. Its totient is φ = 782364614400.
The previous prime is 1013331213413. The next prime is 1013331213469. The reversal of 1013331213433 is 3343121333101.
It is a cyclic number.
It is not a de Polignac number, because 1013331213433 - 213 = 1013331205241 is a prime.
It is not an unprimeable number, because it can be changed into a prime (1013331213413) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 60359248 + ... + 60376033.
It is an arithmetic number, because the mean of its divisors is an integer number (79685286120).
Almost surely, 21013331213433 is an apocalyptic number.
It is an amenable number.
1013331213433 is a deficient number, since it is larger than the sum of its proper divisors (261633364487).
1013331213433 is a wasteful number, since it uses less digits than its factorization.
1013331213433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 120735408.
The product of its (nonzero) digits is 5832, while the sum is 28.
Adding to 1013331213433 its reverse (3343121333101), we get a palindrome (4356452546534).
The spelling of 1013331213433 in words is "one trillion, thirteen billion, three hundred thirty-one million, two hundred thirteen thousand, four hundred thirty-three".
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