1013331321433 has 4 divisors (see below), whose sum is σ = 1046019428608. Its totient is φ = 980643214260.

The previous prime is 1013331321419. The next prime is 1013331321461. The reversal of 1013331321433 is 3341231333101.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013331321433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1013331321733) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16344053541 + ... + 16344053602.

It is an arithmetic number, because the mean of its divisors is an integer number (261504857152).

Almost surely, 2^{1013331321433} is an apocalyptic number.

It is an amenable number.

1013331321433 is a deficient number, since it is larger than the sum of its proper divisors (32688107175).

1013331321433 is an equidigital number, since it uses as much as digits as its factorization.

1013331321433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 32688107174.

The product of its (nonzero) digits is 5832, while the sum is 28.

Adding to 1013331321433 its reverse (3341231333101), we get a palindrome (4354562654534).

The spelling of 1013331321433 in words is "one trillion, thirteen billion, three hundred thirty-one million, three hundred twenty-one thousand, four hundred thirty-three".