Base | Representation |
---|---|
bin | 11101011111100111111… |
… | …00111001001111011011 |
3 | 10120212210021222011211101 |
4 | 32233303330321033123 |
5 | 113100430444004042 |
6 | 2053315412212231 |
7 | 133134151033315 |
oct | 16576374711733 |
9 | 3525707864741 |
10 | 1013410141147 |
11 | 36086a672478 |
12 | 1444a500a077 |
13 | 7474461c9c1 |
14 | 370994567b5 |
15 | 1b563bd16b7 |
hex | ebf3f393db |
1013410141147 has 2 divisors, whose sum is σ = 1013410141148. Its totient is φ = 1013410141146.
The previous prime is 1013410141069. The next prime is 1013410141187. The reversal of 1013410141147 is 7411410143101.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1013410141147 is a prime.
It is a super-2 number, since 2×10134101411472 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1013410141187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506705070573 + 506705070574.
It is an arithmetic number, because the mean of its divisors is an integer number (506705070574).
Almost surely, 21013410141147 is an apocalyptic number.
1013410141147 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013410141147 is an equidigital number, since it uses as much as digits as its factorization.
1013410141147 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 1013410141147 its reverse (7411410143101), we get a palindrome (8424820284248).
The spelling of 1013410141147 in words is "one trillion, thirteen billion, four hundred ten million, one hundred forty-one thousand, one hundred forty-seven".
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