1013413011419 has 2 divisors, whose sum is σ = 1013413011420. Its totient is φ = 1013413011418.

The previous prime is 1013413011383. The next prime is 1013413011427. The reversal of 1013413011419 is 9141103143101.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1013413011419 is a prime.

It is a super-3 number, since 3×1013413011419³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 1013413011391 and 1013413011400.

It is not a weakly prime, because it can be changed into another prime (1013413011469) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506706505709 + 506706505710.

It is an arithmetic number, because the mean of its divisors is an integer number (506706505710).

Almost surely, 2^{1013413011419} is an apocalyptic number.

1013413011419 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013413011419 is an equidigital number, since it uses as much as digits as its factorization.

1013413011419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 1013413011419 in words is "one trillion, thirteen billion, four hundred thirteen million, eleven thousand, four hundred nineteen".