Base | Representation |
---|---|
bin | 11101011111101001101… |
… | …11000111010011111011 |
3 | 10120212211100200120100001 |
4 | 32233310313013103323 |
5 | 113100443400400011 |
6 | 2053321115253431 |
7 | 133134424540021 |
oct | 16576467072373 |
9 | 3525740616301 |
10 | 1013425403131 |
11 | 360878246a89 |
12 | 1444aa14a277 |
13 | 7474783466b |
14 | 3709b4aa711 |
15 | 1b5651e87c1 |
hex | ebf4dc74fb |
1013425403131 has 2 divisors, whose sum is σ = 1013425403132. Its totient is φ = 1013425403130.
The previous prime is 1013425403077. The next prime is 1013425403213. The reversal of 1013425403131 is 1313045243101.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1013425403131 - 211 = 1013425401083 is a prime.
It is a super-2 number, since 2×10134254031312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1013425403131.
It is not a weakly prime, because it can be changed into another prime (1013425403531) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506712701565 + 506712701566.
It is an arithmetic number, because the mean of its divisors is an integer number (506712701566).
Almost surely, 21013425403131 is an apocalyptic number.
1013425403131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1013425403131 is an equidigital number, since it uses as much as digits as its factorization.
1013425403131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
The spelling of 1013425403131 in words is "one trillion, thirteen billion, four hundred twenty-five million, four hundred three thousand, one hundred thirty-one".
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