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1013442432113 is a prime number
BaseRepresentation
bin11101011111101011110…
…00000100110001110001
310120212212112201201201002
432233311320010301301
5113101012230311423
62053322524251345
7133135022353136
oct16576570046161
93525775651632
101013442432113
11360886918121
121444b39a0b55
137474b217697
143709d86058d
151b56695e228
hexebf5e04c71

1013442432113 has 2 divisors, whose sum is σ = 1013442432114. Its totient is φ = 1013442432112.

The previous prime is 1013442432109. The next prime is 1013442432137. The reversal of 1013442432113 is 3112342443101.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 778573287424 + 234869144689 = 882368^2 + 484633^2 .

It is an emirp because it is prime and its reverse (3112342443101) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1013442432113 - 22 = 1013442432109 is a prime.

It is a super-2 number, since 2×10134424321132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1013442492113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 506721216056 + 506721216057.

It is an arithmetic number, because the mean of its divisors is an integer number (506721216057).

Almost surely, 21013442432113 is an apocalyptic number.

It is an amenable number.

1013442432113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1013442432113 is an equidigital number, since it uses as much as digits as its factorization.

1013442432113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 1013442432113 its reverse (3112342443101), we get a palindrome (4125784875214).

The spelling of 1013442432113 in words is "one trillion, thirteen billion, four hundred forty-two million, four hundred thirty-two thousand, one hundred thirteen".