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10141054411 = 12498119339
BaseRepresentation
bin10010111000111010…
…00011010111001011
3222011202011221101211
421130131003113023
5131232102220121
64354141553551
7506206353205
oct113435032713
928152157354
1010141054411
1143343a7304
121b702758b7
13c57ca6717
146c2b9d775
153e5471ce1
hex25c7435cb

10141054411 has 4 divisors (see below), whose sum is σ = 10149175000. Its totient is φ = 10132933824.

The previous prime is 10141054409. The next prime is 10141054423. The reversal of 10141054411 is 11445014101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10141054411 - 21 = 10141054409 is a prime.

It is a super-3 number, since 3×101410544113 (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10141054481) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4058421 + ... + 4060918.

It is an arithmetic number, because the mean of its divisors is an integer number (2537293750).

Almost surely, 210141054411 is an apocalyptic number.

10141054411 is a deficient number, since it is larger than the sum of its proper divisors (8120589).

10141054411 is an equidigital number, since it uses as much as digits as its factorization.

10141054411 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8120588.

The product of its (nonzero) digits is 320, while the sum is 22.

Adding to 10141054411 its reverse (11445014101), we get a palindrome (21586068512).

The spelling of 10141054411 in words is "ten billion, one hundred forty-one million, fifty-four thousand, four hundred eleven".

Divisors: 1 1249 8119339 10141054411