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10142563255403 = 16760733911709
BaseRepresentation
bin1001001110010111111111…
…1000010100010001101011
31022220121201200010222221212
42103211333320110101223
52312133432143133103
633323232414223335
72064530113125365
oct223457770242153
938817650128855
1010142563255403
1132604895a5957
121179843ab4b4b
13587593a96597
14270c8cd55d35
15128c70bd77d8
hex9397fe1446b

10142563255403 has 4 divisors (see below), whose sum is σ = 10203297167280. Its totient is φ = 10081829343528.

The previous prime is 10142563255393. The next prime is 10142563255417. The reversal of 10142563255403 is 30455236524101.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 10142563255403 - 28 = 10142563255147 is a prime.

It is a super-2 number, since 2×101425632554032 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (10142563255603) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30366955688 + ... + 30366956021.

It is an arithmetic number, because the mean of its divisors is an integer number (2550824291820).

Almost surely, 210142563255403 is an apocalyptic number.

10142563255403 is a deficient number, since it is larger than the sum of its proper divisors (60733911877).

10142563255403 is an equidigital number, since it uses as much as digits as its factorization.

10142563255403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60733911876.

The product of its (nonzero) digits is 432000, while the sum is 41.

Adding to 10142563255403 its reverse (30455236524101), we get a palindrome (40597799779504).

The spelling of 10142563255403 in words is "ten trillion, one hundred forty-two billion, five hundred sixty-three million, two hundred fifty-five thousand, four hundred three".

Divisors: 1 167 60733911709 10142563255403