Base | Representation |
---|---|
bin | 11101100001001111111… |
… | …11011011001011100001 |
3 | 10120222001010211011102101 |
4 | 32300213333123023201 |
5 | 113104223001012211 |
6 | 2053542201250401 |
7 | 133164612054634 |
oct | 16604777331341 |
9 | 3528033734371 |
10 | 1014283219681 |
11 | 361178487286 |
12 | 1446a9493a01 |
13 | 7485347b714 |
14 | 3713d3a5c1b |
15 | 1b5b56915c1 |
hex | ec27fdb2e1 |
1014283219681 has 2 divisors, whose sum is σ = 1014283219682. Its totient is φ = 1014283219680.
The previous prime is 1014283219657. The next prime is 1014283219693. The reversal of 1014283219681 is 1869123824101.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 913857609681 + 100425610000 = 955959^2 + 316900^2 .
It is a cyclic number.
It is not a de Polignac number, because 1014283219681 - 225 = 1014249665249 is a prime.
It is a super-2 number, since 2×10142832196812 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1014283219981) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507141609840 + 507141609841.
It is an arithmetic number, because the mean of its divisors is an integer number (507141609841).
Almost surely, 21014283219681 is an apocalyptic number.
It is an amenable number.
1014283219681 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014283219681 is an equidigital number, since it uses as much as digits as its factorization.
1014283219681 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 165888, while the sum is 46.
The spelling of 1014283219681 in words is "one trillion, fourteen billion, two hundred eighty-three million, two hundred nineteen thousand, six hundred eighty-one".
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