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101433230113 is a prime number
BaseRepresentation
bin101111001110111100…
…1000100001100100001
3100200211001111222100111
41132131321010030201
53130213401330423
6114333042051321
710220416141645
oct1363571041441
9320731458314
10101433230113
113a0214610a6
12177a9949b41
1397467244b7
144ca3542c25
152989e9560d
hex179de44321

101433230113 has 2 divisors, whose sum is σ = 101433230114. Its totient is φ = 101433230112.

The previous prime is 101433230071. The next prime is 101433230153. The reversal of 101433230113 is 311032334101.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 72893520144 + 28539709969 = 269988^2 + 168937^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-101433230113 is a prime.

It is not a weakly prime, because it can be changed into another prime (101433230153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 50716615056 + 50716615057.

It is an arithmetic number, because the mean of its divisors is an integer number (50716615057).

Almost surely, 2101433230113 is an apocalyptic number.

It is an amenable number.

101433230113 is a deficient number, since it is larger than the sum of its proper divisors (1).

101433230113 is an equidigital number, since it uses as much as digits as its factorization.

101433230113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 101433230113 its reverse (311032334101), we get a palindrome (412465564214).

The spelling of 101433230113 in words is "one hundred one billion, four hundred thirty-three million, two hundred thirty thousand, one hundred thirteen".