Base | Representation |
---|---|
bin | 10010111001001011… |
… | …01111011010011001 |
3 | 222011220110122122201 |
4 | 21130211233122121 |
5 | 131233143110433 |
6 | 4354302450201 |
7 | 506234620324 |
oct | 113445573231 |
9 | 28156418581 |
10 | 10143331993 |
11 | 4335712503 |
12 | 1b70b93961 |
13 | c585c32c2 |
14 | 6c31d37bb |
15 | 3e5771a7d |
hex | 25c96f699 |
10143331993 has 2 divisors, whose sum is σ = 10143331994. Its totient is φ = 10143331992.
The previous prime is 10143331987. The next prime is 10143332057. The reversal of 10143331993 is 39913334101.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8295019929 + 1848312064 = 91077^2 + 42992^2 .
It is an emirp because it is prime and its reverse (39913334101) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 10143331993 - 29 = 10143331481 is a prime.
It is not a weakly prime, because it can be changed into another prime (10143331193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071665996 + 5071665997.
It is an arithmetic number, because the mean of its divisors is an integer number (5071665997).
Almost surely, 210143331993 is an apocalyptic number.
It is an amenable number.
10143331993 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143331993 is an equidigital number, since it uses as much as digits as its factorization.
10143331993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 37.
The spelling of 10143331993 in words is "ten billion, one hundred forty-three million, three hundred thirty-one thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.120 sec. • engine limits •