Base | Representation |
---|---|
bin | 1001001110011011001110… |
… | …0011001100000111101001 |
3 | 1022220200222002022220100221 |
4 | 2103212303203030013221 |
5 | 2312142221103212301 |
6 | 33323454422330041 |
7 | 2064560440350112 |
oct | 223466343140751 |
9 | 38820862286327 |
10 | 10143430132201 |
11 | 3260893964263 |
12 | 1179a46289921 |
13 | 5876a1563532 |
14 | 270d3212d209 |
15 | 128cc1d6eda1 |
hex | 939b38cc1e9 |
10143430132201 has 2 divisors, whose sum is σ = 10143430132202. Its totient is φ = 10143430132200.
The previous prime is 10143430132163. The next prime is 10143430132207. The reversal of 10143430132201 is 10223103434101.
10143430132201 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10085324547600 + 58105584601 = 3175740^2 + 241051^2 .
It is a cyclic number.
It is not a de Polignac number, because 10143430132201 - 223 = 10143421743593 is a prime.
It is not a weakly prime, because it can be changed into another prime (10143430132207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5071715066100 + 5071715066101.
It is an arithmetic number, because the mean of its divisors is an integer number (5071715066101).
Almost surely, 210143430132201 is an apocalyptic number.
It is an amenable number.
10143430132201 is a deficient number, since it is larger than the sum of its proper divisors (1).
10143430132201 is an equidigital number, since it uses as much as digits as its factorization.
10143430132201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 10143430132201 its reverse (10223103434101), we get a palindrome (20366533566302).
The spelling of 10143430132201 in words is "ten trillion, one hundred forty-three billion, four hundred thirty million, one hundred thirty-two thousand, two hundred one".
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