Base | Representation |
---|---|
bin | 11101100001011110000… |
… | …01100011111001000011 |
3 | 10120222100100212012122121 |
4 | 32300233001203321003 |
5 | 113104443203021123 |
6 | 2054002014345111 |
7 | 133200544050442 |
oct | 16605701437103 |
9 | 3528310765577 |
10 | 1014401220163 |
11 | 361229052841 |
12 | 144720abb197 |
13 | 74871a554a6 |
14 | 37150d20d59 |
15 | 1b5c0bee75d |
hex | ec2f063e43 |
1014401220163 has 2 divisors, whose sum is σ = 1014401220164. Its totient is φ = 1014401220162.
The previous prime is 1014401220037. The next prime is 1014401220251. The reversal of 1014401220163 is 3610221044101.
1014401220163 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1014401220163 is a prime.
It is not a weakly prime, because it can be changed into another prime (1014401230163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 507200610081 + 507200610082.
It is an arithmetic number, because the mean of its divisors is an integer number (507200610082).
Almost surely, 21014401220163 is an apocalyptic number.
1014401220163 is a deficient number, since it is larger than the sum of its proper divisors (1).
1014401220163 is an equidigital number, since it uses as much as digits as its factorization.
1014401220163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 1014401220163 its reverse (3610221044101), we get a palindrome (4624622264264).
The spelling of 1014401220163 in words is "one trillion, fourteen billion, four hundred one million, two hundred twenty thousand, one hundred sixty-three".
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