Base | Representation |
---|---|
bin | 11101100001111100111… |
… | …01100111110001101001 |
3 | 10121000000102020111022110 |
4 | 32300332131213301221 |
5 | 113111011004444340 |
6 | 2054043430112533 |
7 | 133210140455022 |
oct | 16607635476151 |
9 | 3530012214273 |
10 | 1014660234345 |
11 | 361351282a4a |
12 | 1447937ab749 |
13 | 748b3602b14 |
14 | 371774a5c49 |
15 | 1b5d8814680 |
hex | ec3e767c69 |
1014660234345 has 16 divisors (see below), whose sum is σ = 1645695505152. Its totient is φ = 533739081600.
The previous prime is 1014660234337. The next prime is 1014660234353. The reversal of 1014660234345 is 5434320664101.
It is an interprime number because it is at equal distance from previous prime (1014660234337) and next prime (1014660234353).
It is not a de Polignac number, because 1014660234345 - 23 = 1014660234337 is a prime.
It is a super-2 number, since 2×10146602343452 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 463314081 + ... + 463316270.
It is an arithmetic number, because the mean of its divisors is an integer number (102855969072).
Almost surely, 21014660234345 is an apocalyptic number.
1014660234345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1014660234345 is a deficient number, since it is larger than the sum of its proper divisors (631035270807).
1014660234345 is an equidigital number, since it uses as much as digits as its factorization.
1014660234345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 926630432.
The product of its (nonzero) digits is 207360, while the sum is 39.
Adding to 1014660234345 its reverse (5434320664101), we get a palindrome (6448980898446).
The spelling of 1014660234345 in words is "one trillion, fourteen billion, six hundred sixty million, two hundred thirty-four thousand, three hundred forty-five".
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